Steel beam torsion design (SCI-P-057): Total applied torque
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Tekla Tedds
Tekla Tedds for Word
Environment
British Standard
Total applied torque – is this the total applied torque as the name suggests, or is it the max torsional force in the beam?
Example; A 4 m long beam with a uniform applied torque of 0.4 kNm/m would have a total applied torque of 0.4x4 = 1.6kNm, but the max torsional force in the beam would be half this.
The completed example calculations stored in the Tedds Library are actually the worked examples from the guide:
‘I section with single torsional point load example’ is Example 1 starting pg 18 of the guide – for a point load of 100kN applied at an eccentricity of 75mm the Total applied torque entered is Tq=7.5kNm, not 3.75kNm which is To – please see pg 31 of the guide.
‘I section in torsion example’ is Example 5 starting on pg 46. Tq is entered as 6 kNm
Example; A 4 m long beam with a uniform applied torque of 0.4 kNm/m would have a total applied torque of 0.4x4 = 1.6kNm, but the max torsional force in the beam would be half this.
Solution
The value you enter is the total torque (1.6 kNm in the above example) as per SCI-P-057.The completed example calculations stored in the Tedds Library are actually the worked examples from the guide:
‘I section with single torsional point load example’ is Example 1 starting pg 18 of the guide – for a point load of 100kN applied at an eccentricity of 75mm the Total applied torque entered is Tq=7.5kNm, not 3.75kNm which is To – please see pg 31 of the guide.
‘I section in torsion example’ is Example 5 starting on pg 46. Tq is entered as 6 kNm